Another Super Over should decide winner: Tendulkar

Kane Williamson

Kane Williamson

Cricketing legend Sachin Tendulkar has selceted 5 Indians players in his ICC Cricket World Cup all-star XI but preferred to go with England's Jonny Bairstow over India's Mahendra Singh Dhoni as the team's wicketkeeper.

Little Master chose four all-rounders for his World Cup XI.

Tendulkar picked Williamson, who was adjudged the player of the tournament, besides including Bangladesh all-rounder Shakib Al Hasan, who had take 11 wickets and amassed over 600 runs in the World Cup.

Tendulkar's World Cup 2019 XI: Rohit Sharma, Jonny Bairstow (wk), Kane Williamson (c), Virat Kohli, Shakib Al Hasan, Hardik Pandya, Ben Stokes, Ravindra Jadeja, Mitchell Starc, Jofra Archer, Jasprit Bumrah.

Sachin Tendulkar on Tuesday endorsed a second super over to decide the victor instead of considering the boundary count if such an extraordinary situation arises like it did in the World Cup final.

Williamson comes in at No.3 and will captain the side. He scored 578 runs and captains the side.

Joe Root will come in at No.4 for this team after a World Cup that saw him finish as England's top run scorer, fifth overall in the tournament, with tons against Pakistan and West Indies and three half centuries.

England all-rounder Ben Stokes ended the tournament at a career-best 694 points, gaining five places and moving into the top 20 and to within two places of his career best of 18th two years ago. Jofra Archer - hero of the Super Over in the final and appearing in his first World Cup - claimed 20 wickets at an impressive economy rate of 4.57 to earn his spot. Jadeja played an outstanding knock in the semi-final match against New Zealand.